Stat Guys I need your help

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Sep 21, 2004
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Ok lets say i have 4 games at 4 different times

10am WY +4 1/2

1PM KY +2 1/2

4PM USC +7 1/2

7PM CAL +2 1/2

What are the odds on all 4 games losing?
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Sep 20, 2004
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The same as all 4 winning: 1 in 16

Don't tell me that you are thinking about doubling up until you win!
 

mhk

"I can't be faded", Dr. Dre
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There is a 1 in 16 chance of losing all 4, (6.25%).
 

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its not as simple as that Guru

Im working on systems

Thanks for the feedback
 

New member
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Statistically its the same as four games at the same time. They are all independent of each other and thus (1/2)^4 or 6.25%
 

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Play first game for 1 unit..if win quit...if lose play 2nd game for 1unit..if lose play 3rd game for 2units,if win 2nd game play 3rd for 1 unit if win quit.If lose 3rd at 2units,play 4th for 5 units if 3rd game won at 2units play 4th for 1 unit,if lose 4th at 5units slice wrist,if miss welcome to my world.
 

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