Math Question of The Day

Glaken · Nov 16, 2004

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You may start with any number and each number may be used only once.

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Glaken · Nov 16, 2004

Brock Landers it was your turn today?

wolfie_cr · Nov 16, 2004

pretty easy to figure out

1) add all numbers (thats 45)
2) substract the final result
3) you get 9, that means only one you are not going to need is 9

piece of cake :drink:

Noreaga+ · Nov 16, 2004

8+9
6+7
1+2

Glaken · Nov 16, 2004

ok Wolfie No more Click for answer tomorrow...

RobFunk · Nov 16, 2004

nega has it, but instead of 1+2 should be 1+5

Glaken · Nov 16, 2004

we're looking for a total here

RobFunk · Nov 16, 2004

8,9,6,7,5,1

wantitall4moi · Nov 16, 2004

There is another answer the key didn't give. Starting at the '3', you run through thr 8,9, down though the 6,7, accroess to the 1, and up to the two. Also starting at the 3 again, down though the 4,5 across through the 2,7 and up through the 6,9. Also starting at the 4, up through the 5,3 across through the 8,9, down through the 6, and over to the 1. 4,2,7,6,8,9, works as well.

There are numersouns answers to this thing, as long as the left over numbers add up to 9, you will be right. As long as the number touch in the right way.