A simple logic problem

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Oh boy!
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I undestand what you are saying but if there is 2 separate chances for 1 boy one girl, why is there not 2 separate chances for 2boys (ba/bb, bb/ba)?

I say the chances are either:

BB
BG (GB is the same thing)

or

BaBb
BG
GB
BbBa

That's an excellent question Kornholio! But you can't have BaBb AND BbBa because one child has already been identified as a boy. The question is asking what OTHER possibilities are there. The problem has already resolved 1 of the pairs, leaving the other pair as a possibility.
 

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Fucking unbelieveable.

I read the 1st page of this thread, and now it is 15 pages long?

The answer is 50%, and there is no arguement.

Here is the proof.

Consider these four statements.

A woman is about to give birth to her first child. What is the probability of it being M/F?

A woman is a mother of one child. What is the probability of it being M/F?

A woman has one child, and is about to give birth to her second child next week. What is the probability of it being M/F?

A woman has two children. She spoke of her eldest being a boy. What is the probability of the second child being M/F?

These fucking four statements say the exact same fucking thing! It's 50%!!

That's why people lose at gambling. Cannot do math. Cannot even read English!

Whew! Glad to get that off my chest, LOL.

:nohead:

This is why people lose at gambling.
 

They drew first blood
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I too have to go with 50%. Doesnt really matter if they already have a boy or girl or any number of kids. Anytime a woman becomes pregant there is a 50/50 shot on what it will be regardless of how many kids they may already have.
 
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This is why people lose at gambling.

It's also why this country is losing it's dominance in math/science. A
total dumbing down of our education system.

We've got so-called "math types" in here that can't figure this out
even though it's been explained to them in every way for
15 pages.
 
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I too have to go with 50%. Doesnt really matter if they already have a boy or girl or any number of kids. Anytime a woman becomes pregant there is a 50/50 shot on what it will be regardless of how many kids they may already have.

That's not the question.

:ohno:
 

Oh boy!
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That's not the question.

:ohno:

Zit, you have the helm.

picard04.jpg
 

They drew first blood
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Stole this from somewhere

P(B) = 0.5
P(G) = 0.5
P(other=G | talkabout=B) = [P(B)P(G) + P(G)P(B)] / [P(B)P(B) + P(B)P(G) + P(G)P(B)]
P(other=G | talkabout=B) = (0.5*0.5 + 0.5*0.5) / (0.5*0.5 + 0.5*0.5 + 0.5*0.5)
P(other=G | talkabout=B) = 0.666667

So: the probability of the other child being a girl is 67%
 

Rx Senior
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I log into therx to see this debate still going....LOL


I'd like to officially change my answer....

my new answer is 100%

what kind of idiot will talk about his son as if he had only one without making reference to if the son is the older or the younger boy....NO DOUBT it is a girl!!!!!


WHOOOOOOTTTT!!!! trying to round up another gang of debaters....join me 100% crew!
 

HAT

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It's also why this country is losing it's dominance in math/science. A
total dumbing down of our education system.

We've got so-called "math types" in here that can't figure this out
even though it's been explained to them in every way for
15 pages.

I would argue that the "math types" are trying to force an equation that isn't there. And while the math is correct based on the way you are interpreting the riddle, you aren't seeing that you are reading too much into a totally irrelevant sentence.


"A man tells you he has two children. He then starts talking about his son.
(meaningless sentence removed)
What is the probability that his other child is a girl?
"

The things we know:
A man has 2 kids
One is a boy

The only question being asked:
What are the chances that the other child is a girl?

There is no difference between GB & BG. There are only two possibilities, he's got 2 boys or one of each.

"Other" does in fact mean "remaining"

Let's say said 'man' was standing in front of us. And said 'son' is also standing in front of us. The "other" child is in a fucking box right next to them. You gonna give me 2 to 1 odds on whether the kid in the box has a dick or a snatch?
 

Oh boy!
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"Other" does in fact mean "remaining"

Let's say said 'man' was standing in front of us. And said 'son' is also standing in front of us. The "other" child is in a fucking box right next to them. You gonna give me 2 to 1 odds on whether the kid in the box has a dick or a snatch?

"Other" does NOT mean "remaining". The scenario you give implies that we know which kid is the son which is a different scenario that was presented in the original problem. In the problem we don't know which kid is a boy. That's the difference.

Just like in shdw01's card scenario. The guy tells us one coin is heads but we don't know which one. That gives us more uncertainty which means we have more possibilities.
 

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It's also why this country is losing it's dominance in math/science. A
total dumbing down of our education system.

We've got so-called "math types" in here that can't figure this out
even though it's been explained to them in every way for
15 pages.

Couldn't have said it better myself.
 

Rx Senior
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Even though we all think the other half of the forum is retarded, I think we should all take comfort in knowing both sides UNDERSTAND the other point of view....I think it is just a debate on how the question is stated and what certain words/phrases ACTUALLY mean.


fwiw, you are all wrong....100% BABY!
 

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Even though we all think the other half of the forum is retarded, I think we should all take comfort in knowing both sides UNDERSTAND the other point of view....I think it is just a debate on how the question is stated and what certain words/phrases ACTUALLY mean.


fwiw, you are all wrong....100% BABY!

Yeah, I understand after 16 pages and counting we have some really stupid fucks around here. Not only that, I've noticed a lot of people have problems reading properly too. The sad part about all this is, even after it's explained and proven why 2/3 is the right answer, there are still plenty who can't accept it and believe 50% is still right. This country is in downward spiral.
 

HAT

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"Other" does NOT mean "remaining". The scenario you give implies that we know which kid is the son which is a different scenario that was presented in the original problem. In the problem we don't know which kid is a boy. That's the difference.

I hear ya QL, but that begs another question?

Where in the original post does it say that we do NOT know "which" kid is the son?

A man tells you he has two children. He then starts talking about his son. He does not tell you whether the son is the oldest child or the youngest child. What is the probability that his other child is a girl?

The second sentence is completely and utterly meaningless and leading the "math types" astray.

It may as well read:

A man tells you he has two children. He then starts talking about his son. He does not tell you whether his wife has herpes. What is the probability that his other child is a girl?

It matters not what he DOESN"T tell you. The ONLY two facts we know are that he has 2 kids and one is a boy.

If this little bastard is telling us the truth....ONE of his kids has male parts. What does the OTHER one have? The are only two possibilities.

This is more of a reading comprehension question than a math problem.
 

Oh boy!
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I hear ya QL, but that begs another question?

Where in the original post does it say that we do NOT know "which" kid is the son?

If it is not explicitly told to us in the problem then it's not known to us, right?
 

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