Kwo
New member
- Joined
- Jan 14, 2005
- Messages
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I have a question for anyone who wants to take the time to explain.
In another post, which i hesitate to reference because I don't want to see a bunch of arguing here, another user referred to the potential advantages of using parlays (two-team, I believe) to enhance profits.
I can't figure out a scenario where this would be effective. I am sure I'm missing something given the general knowledge level of the individual who posted it.
As far as I can tell, if you bet five games (A,B,C,D & E) and parlayed every two-team combination rather than straight bets on each game, you would come out behind, even hitting 60% of the games.
Here's my math and you can tell me where i'm wrong:
if A,B, & C win (60% of your nightly 5 bets), you have three parlays that win:
AB, AC & BC. If you had bet 11 to win 10, that would create 85.80 in winnings and -77 in losses, for a net win of $8.80.
If you had just bet straight the same total $110 on the five games involved, the same 60% would net you 60 (lay 22 to win 20 x 3) in winnings less 44 (22 per 2 losses) in losses for a net of $16.
What am i missing?
Thanks in advance to all you math gurus out there,
Kwo
In another post, which i hesitate to reference because I don't want to see a bunch of arguing here, another user referred to the potential advantages of using parlays (two-team, I believe) to enhance profits.
I can't figure out a scenario where this would be effective. I am sure I'm missing something given the general knowledge level of the individual who posted it.
As far as I can tell, if you bet five games (A,B,C,D & E) and parlayed every two-team combination rather than straight bets on each game, you would come out behind, even hitting 60% of the games.
Here's my math and you can tell me where i'm wrong:
if A,B, & C win (60% of your nightly 5 bets), you have three parlays that win:
AB, AC & BC. If you had bet 11 to win 10, that would create 85.80 in winnings and -77 in losses, for a net win of $8.80.
If you had just bet straight the same total $110 on the five games involved, the same 60% would net you 60 (lay 22 to win 20 x 3) in winnings less 44 (22 per 2 losses) in losses for a net of $16.
What am i missing?
Thanks in advance to all you math gurus out there,
Kwo