if i show you 761 winners and 43 losers ( 94.6%) , is it worth it to lay 9 to 1 ?

[WorldNumberOne]

on a 2 teamer ?

only 43 possible times that you could have lost a game...

their have 72 days out of 110 that you couldnt have possibly lost at all..

do you lay it ?

 

[Dante]

 

[Illini]

on a 2 teamer ?

only 43 possible times that you could have lost a game...

their have 72 days out of 110 that you couldnt have possibly lost at all..

do you lay it ?

Try English, bro. Works better that way.

 

[WorldNumberOne]

do that mean no dante ?

 

[trytrytry]

Mr World



It means nobody yet can figure out what you are asking.



ask again in more detail....

 

[WorldNumberOne]

Try English, bro. Works better that way.

whats not english ?

under this scenario which has happened by the way , 761 wins and 43 losses , do you lay 9 to 1 on a 2 teamer ?

i realize laying 9-1 under almost every circumstance is idiotic , but what about this one .

 

[trytrytry]

is this a money line 2 team parlay of some sort?

 

[Dante]

do that mean no dante ?

that do mean I have no idea what your wanting to know

 

[WorldNumberOne]

2 team NBA 16 point teasers. lay 9-1

804 games played .

if you take the 16 and add it to the dog you won 761 times.

on another note , their were 693 middles.

 

[trytrytry]

this is a question for Fishead. Im sure he will check on it for you!

 

[Illini]

I would say that if your results are enough of a sample to know that it is certain to continue in the same way, then yes you lay 9 for 1. You would win a lot of money over time. But I would have no idea if your data is enough to make that assumption, that's your call. I was just playing about the English comment. Although I was unsure what you meant, exactly.

 

[WorldNumberOne]

I would say that if your results are enough of a sample to know that it is certain to continue in the same way, then yes you lay 9 for 1. You would win a lot of money over time. But I would have no idea if your data is enough to make that assumption, that's your call. I was just playing about the English comment. Although I was unsure what you meant, exactly.

i would say 804 games is a decent sample size.. thats the entire season so far.

i was also seeing if i would get responses based on just the % , not where it came from and how..

 

[Fishhead]

i would say 804 games is a decent sample size.. thats the entire season so far.

i was also seeing if i would get responses based on just the % , not where it came from and how..

Not near a big enough sample in my estimation............I would try and look at least 3 years, and probaby five.

Hope for nothing significant terrible in one year(hopefully profitable each year) and a winner overall for those five years.

---FISH---

 

[WorldNumberOne]

Not near a big enough sample in my estimation............I would try and look at least 3 years, and probaby five.

Hope for nothing significant terrible in one year(hopefully profitable each year) and a winner overall for those five years.

---FISH---

for arguments sake lets say the win % of 94.6 pans out over 3 years , is it a good move to lay 9-1 ?

 

[wantitall4moi]

Well you have shown that it has about a -1475 value (if my mathis right), then laying -900 is obviously profittable.


So basically if you had done it all year in every scenario you would have collected $76100 (761 x $100) and lost $38700 ($900 x 43) for an overall profit of $37400.

 

[WorldNumberOne]

not sure you can just take 761 and multiply it by 100. you had to make a 2 team play.

i'm not sure i'm following your math on that one..

i guess my question revolved more around the fact you had over 94 % in winning single picks. when you had to couple them did the randomness of having to put 2 teams together diminish your odds to where laying 9-1 was a bad idea.

any other math wiz's want to take a crack at this ?

i'm inclined to think that you give any good handicapper 16 points in basketball and only ask them to find 2 winners , they will lay 9-1 all day and all night..

especially if you have 2 eastern conference teams playing one another where the score is apt to be in the 90's . or 2 college teams that average about 60 points a game each..

 

[Woody0]

If this is the question:

"Should I play a 2 teamer if the probability of each team winning is 94.6% and I am laying 9 to win 1"

then the answer is no.

The probability of both teams winning is 0.946 X 0.946 = 0.8949 or 89.49%. So in 10,000 plays you win 8949 units and lose 1051 X 9 = 9459 units for a loss of 510 units.

If this is not your question then I cannot understand what you are asking.